2020 Advent of Code solutions in various languages
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# --- Day 5: Binary Boarding ---
#
# You board your plane only to discover a new problem: you dropped your boarding
# pass! You aren't sure which seat is yours, and all of the flight attendants
# are busy with the flood of people that suddenly made it through passport
# control.
#
# You write a quick program to use your phone's camera to scan all of the nearby
# boarding passes (your puzzle input); perhaps you can find your seat through
# process of elimination.
#
# Instead of zones or groups, this airline uses binary space partitioning to
# seat people. A seat might be specified like FBFBBFFRLR, where F means "front",
# B means "back", L means "left", and R means "right".
#
# The first 7 characters will either be F or B; these specify exactly one of
# the 128 rows on the plane (numbered 0 through 127). Each letter tells you
# which half of a region the given seat is in. Start with the whole list of
# rows; the first letter indicates whether the seat is in the front
# (0 through 63) or the back (64 through 127). The next letter indicates which
# half of that region the seat is in, and so on until you're left with
# exactly one row.
#
# For example, consider just the first seven characters of FBFBBFFRLR:
#
# Start by considering the whole range, rows 0 through 127.
# F means to take the lower half, keeping rows 0 through 63.
# B means to take the upper half, keeping rows 32 through 63.
# F means to take the lower half, keeping rows 32 through 47.
# B means to take the upper half, keeping rows 40 through 47.
# B keeps rows 44 through 47.
# F keeps rows 44 through 45.
#
# The final F keeps the lower of the two, row 44.
#
# The last three characters will be either L or R; these specify exactly one
# of the 8 columns of seats on the plane (numbered 0 through 7). The same
# process as above proceeds again, this time with only three steps. L means
# to keep the lower half, while R means to keep the upper half.
#
# For example, consider just the last 3 characters of FBFBBFFRLR:
#
# Start by considering the whole range, columns 0 through 7.
# R means to take the upper half, keeping columns 4 through 7.
# L means to take the lower half, keeping columns 4 through 5.
# The final R keeps the upper of the two, column 5.
#
# So, decoding FBFBBFFRLR reveals that it is the seat at row 44, column 5.
#
# Every seat also has a unique seat ID: multiply the row by 8, then add the
# column. In this example, the seat has ID 44 * 8 + 5 = 357.
#
# Here are some other boarding passes:
#
# BFFFBBFRRR: row 70, column 7, seat ID 567.
# FFFBBBFRRR: row 14, column 7, seat ID 119.
# BBFFBBFRLL: row 102, column 4, seat ID 820.
#
# As a sanity check, look through your list of boarding passes. What is the
# highest seat ID on a boarding pass?
library(tidyverse)
input <- readLines("../input/05-01.txt")
partition <- function(seq, lb, ub, trigger) {
for (part in seq) {
amt <- floor((ub - lb)/2) + 1
if (part == trigger) {
ub <- ub - amt
} else {
lb <- lb + amt
}
}
return(if (tail(seq, 1) == trigger) ub else lb)
}
strsplit(input, "") %>%
map_dbl(~{
(partition(.x[1:7], 0, 127, "F") * 8) + partition(.x[8:10], 0, 7, "L")
}) %>%
sort() -> seats
max(seats)
# --- Part Two ---
#
# Ding! The "fasten seat belt" signs have turned on. Time to find your seat.
#
# It's a completely full flight, so your seat should be the only missing
# boarding pass in your list. However, there's a catch: some of the seats at
# the very front and back of the plane don't exist on this aircraft, so they'll
# be missing from your list as well.
#
# Your seat wasn't at the very front or back, though; the seats with IDs +1
# and -1 from yours will be in your list.
#
# What is the ID of your seat?
seats[which(diff(c(seats)) > 1)] + 1